Math, asked by rajshah12345, 1 year ago

Pl....................................

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Answered by Anonymous
8
\huge\underline{Answer:-}

( \frac{1}{3} x - y + 5z)

( \frac{1}{9} {x}^{2} + {y}^{2} + 25 {z}^{2} + 5xy - \frac{5}{3} xz + 3xy)



\textbf{Step - By- Step - Solution:-}


\textbf{Using,theorm}

 {a}^{3} + {b}^{3} + {c}^{3} - 3abc

 = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ac - bc - ca)



\textbf{Given ,Equation}

 \frac{1}{27 } {x}^{3} - {y}^{3} + 125 {z}^{3} + 5xyz = 0


\textbf{Step 1 :-}

 { (\frac{1}{3}) }^{3} + {y}^{3} + 5 {z}^{3} + 3( \frac{1}{3}x )(y)(5z)


\textbf{Step 2:-}

( \frac{1}{3} x - y + 5z)

[ { \: (\frac{1}{3}x) }^{2} { - (y)}^{2} + {(5z)}^{2}

 - ( - y)(5z) - ( \frac{1}{3}x) (5z) - (\frac{1}{3} x)( - y)]


\textbf{Step 3:-}

( \frac{1}{3} x - y + 5z)

( \frac{1}{9} {x}^{2} + {y}^{2} + 25 {z}^{2} + 5xy - \frac{5}{3} xz + 3xy)


\huge\underline{Hence:-}

Factores are

<marquee>
( \frac{1}{3} x - y + 5z)

( \frac{1}{9} {x}^{2} + {y}^{2} + 25 {z}^{2} + 5xy - \frac{5}{3} xz + 3xy)

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