Question

pl ans this q fast now only.giving 30 points​

Answer 1

Answer:

area of triangle ADL=area of triangle FBC=1/2 area of rectangle EADL

Answer 2

Step-by-step explanation:

As EDLA is a rectangle

Therefore, ED is equal and parallel to LA

So,

EDLA is a parallelogram

And the diagnosis of a parallelogram bisects it into two congruent triangles

By this we conclude that

Area of EDLA = 2* 12 = 24cm2

Area of FBC = DLA = 12cm2

Hope it helps you

please mark as brainliest