Question

pl ans this que in pic

Answer 1

this method will be used

Answer 2

Step-by-step explanation:

Given Equation is 3x² - 4√3x + 4 = 0   ----- (i)

Comparing with ax² + bx + c = 0, we get

a = 3, b = -4√3, c = 4.

We know that:

D = b² - 4ac

   = (-4√3)² - 4(3)(4)

   = 48 - 48

   = 0

Since, D = 0.The equation has equal real roots.

⇄ Completing Square Method ⇆:

Given Equation is 3x² - 4√3x + 4 = 0

Divide whole equation by 3,

x² - (4√3/3)x + (4/3) = 0

x² - (4/√3)x + (4/3) = 0

Adding and subtracting (2/√3)² on both sides, we get

⇒ x² - (4/√3)x + (4/3) + (2/√3)² - (2/√3)² = 0

⇒ x² - (4/√3)x + (2/√3)² = (2/√3)² - (4/3)

⇒ x² - (4/√3)x + (2/√3)² = 4/3 - 4/3

⇒ (x - 2/√3)² = 0

⇒ x = (2/√3)

⇒ x = (2/√3).

⇄ Verification ⇆:

Substitute x = (2/√3) in (i), we get

⇒ 3(2/√3)² - 4√3(2/√3) + 4 = 0

⇒ 3(4/3) - 8 + 4 = 0

⇒ 4 - 8 + 4 = 0

⇒ 0 = 0.

Hope it helps!