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here is ur answer
.....hope it helps
.....hope it helps
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question:-sin∧2 theta/cos theta + cos theta = sec theta
solution:- taking the LCM of denominators cos theta and 1
LCM is cos theta
LHS=> (sin∧2 theta + cos∧2 theta)/ cos theta
IDENTITY :-(sin∧2 theta + cos∧2 theta = 1)
=> 1/cos theta
=> sec theta
LHS =RHS
hence proved..!!
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