Question

Pl find the angle BCD , given is angle AOB=92 , and given angle EBC=108.
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Answer 1

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Answer 2

Join BD.

∠ADC = ∠EBC = 108° (The exterior angle of a cyclic quadrilateral is equal to the interior opposite angle)

∠ADB = $\frac{1}{2}$ × ∠AOB =$\frac{1}{2}$ ×92° = 46° ( Angles subtended by chord AB at centre and on the circumference)

∠BDC = ∠ADC - ∠ADB = 108° - 46° = 62°