Question

pl find the answer in deatil

Answer 1

Answer:49

Step-by-step explanation:

<KOL =180-82

=98

<KJL=1/2<KOL(as angle in the centre is twice the angle in any part of the circumference of the circle)

=49

Answer 2

In the given figure, we have to find angle KJL, given that angle MOL is 82° and KM and JL are the diameters.

So, since KM and JL are diameters, they will be straight lines. Hence, angle KOJ = 82° (vertically opposite angles)

Now, we know that "angle subtended by a chord at the centre, is double of the angle subtended by it at any point on its circumference"

→ angle KOJ = 2 × angle KLJ

→ 82° = 2 × angle KLJ

→ angle KLJ = 82/2 = 41°

Now, we also know that "angle subtended by diameter of a circle at any point on the circumference is 90°"

Hence, angle JKL = 90°

Now, in ∆JKL

angle JKL + angle KLJ + angle KJL = 180°

(angle sum property of triangle)

→ 90° + 41° + angle KJL = 180°

→ angle KJL = 180° - 131°

→ angle KJL = 49°

Answer :- option 1) 49°