Question

pl give my correct answer tomorrow my exam maths subject and pl give answer with explain​

Answer 1

Answer :

Step-by-step exaplaination :

=>Let P & Q be the points of trisection. Then AP:PB=1:2 & AQ:QB=2:1

Condition-1 :

=>Let P divides AB in ratio 1:2

Hence,

m=1 , m'=2

x=5 , y= -6

x'= -1 , y'= -4

P(x,y)

=P[(mx'+m'x) /(m+m') , (my'+m'y) /(m+m')]

=P[(1)(-1)+(2)(5) /(1+2) , (1)(-4)+(2)(-6) /(1+2)]

=P[(-1+10) /3 , (-4-12) /3]

=P(3 , -16/3)

Condition-2 :

=>Let Q divides AB in ratio 2:1

Hence,

m=2 , m'=1

x=5 , y= -6

x'= -1 , y'= -4

Q(x,y)

=Q[(mx'+m'x) /(m+m') , (my'+m'y) /(m+m')]

=Q[(2)(-1)+(1)(5) /(1+2) , (2)(-4)+(1)(-6) /(1+2)]

=Q[(-2+5) /3 , (-8-6) /3]

=Q(1 , -14/3)

∴ Hence the coordinates of points of trisection are (3,-16/3) & (1,-14/3)