Question

Pl give the ans of Q-11 in image

Answer 1

first

let the third side be 'x'

perimeter = sum of all sides

two sides and perimeter are given so,

1560=510+520+x

x=1560-1030

x=530

the third side =530

now,

for applying heron'S formula

S=1/2 perimeter

S=1/2*1560

S=780

then,

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{780(780 - 510)(780 - 520)(780 - 530)}$

$\sqrt{780 \times 270 \times 260 \times 250}$

117,000 m sq.

117,000 *21=2,457,000 Rs.