Question

pl guys help me with this question​​

Answer 1

Answer:

I) Given in: Triangle ADE

and Angle ADB = ADC = 90 degree.

AD=AD (COMMON)

ii) So, by RHS Rule of congruency, we conclude

△ADB ≅△ADC

iii) Since both triangles are congruent all the corresponding parts will be equal.

So, ∠B=∠C

Step-by-step explanation:

HOPE IT HELP YOU.

ACTUALLY I DON'T KNOW THIS ANSWER IS CORRECT OR NOT.

Answer 2

iii. In ∆ABC as AB=AC so ∠B = ∠C

ii. yes

In triangle ADB and ADC,

AB=AC

As AD is altitude, hence

∠ADB=∠ADC ( 90°)

as AB=AC(given)

so ∠ ABD = ∠ ACD

Therefore ∆ ADB ≈ ∆ ADC

i. Three pairs of equal parts in △ADB and △ADC are-

AB=AC

∠B=∠C

∠ADB=∠ADC

Hope it helps ✌️