Math, asked by Anonymous, 1 year ago

pl help me and tell me why it is wrong

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Answers

Answered by ad9120889
1

Answer:


Step-by-step explanation:

Tan45= Ac/BC

1=1500/BC

Bc=1500.... (1)



Now

Tan30= Ed/Bc+ Cd

1/root3= 1500/1500+CD...... (Bc=1500 from 1)

1500+ CD = 1500root3

CD = 1500 ( root 3 - 1)



Therefore speed = 1500 (root3-1)/ 15

=100 (root3-1)


Hope this is helpful to u

Answered by siddhartharao77
2

Answer:

73 m/sec

Step-by-step explanation:

From figure:

In ΔABD,

tan 45° = BD/AB

⇒ 1 = 1500/AB

⇒ AB = 1500


In ΔACE,

tan 30° = CE/AC

⇒ 1/√3 = 1500/AC

⇒ AC = 1500√3

Now,

BC = AC - AB

      = 1500√3 - 1500

      = 1500(√3 - 1)

      = 1500 * 0.73

      = 1095.


Given, Time taken by the plane in moving from A to B = 15 seconds.

∴ Speed of the flight

= 1095/15 m/sec

= 73 m/sec.


Therefore, the speed of the plane is 73 m/sec.


Hope it helps!

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Anonymous: thanks
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