Math, asked by phanisaimadhav, 9 months ago

pl help me.........tell me the ans

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Answered by spiderman2019
0

Answer:

SinA / SinB

Step-by-step explanation:

Convert TanA and TanB to CotA and CotB.

TanA = xSinB / 1 - xCosB

=> CotA = 1/TanA

              = 1 / [xSinB / 1 - xCosB]

              = 1 - xCosB/xSinB

              = 1/xSinB - xCosB/XSinB

              = 1/xSinB - CotB

=> CotA + CotB = 1/xSinB.  ---------- (i)    

TanB = y SinA/1 - yCosA

=> CotB = 1 / TanB

              = 1/ [ySinA/1 - yCosA]

               = 1 - yCosA/ySinA

               = 1/ySinA - CotA

=> CotB + CotA = 1/ySinA  ----------  (ii)

From (i) and (ii)

1/xSinB = 1/ySinA

=> ySinA = xSinB

=> x/y = SinA / SinB

 

   

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