Question

pl solve and no spam plz​

Answer 1

Answer:

your answer is (........1)

Answer 2

Answer:

Option (A) will be the correct answer.

Step-by-step explanation:

We have,

$\sqrt{1 + \frac{27}{169} } = 1 + \frac{x}{13}$

Squaring both sides

$1 + \frac{27}{169} = 1 + \frac{ {x}^{2} }{169} + \frac{2x}{13} \\ \frac{27}{169} = \frac{ {x}^{2} }{169} + \frac{2x}{13} \\ \frac{27}{13} = \frac{ {x}^{2} }{13} + 2x$

Solving furthur gives,

$\frac{ {x}^{2} }{13} + 2x - \frac{27}{13} = 0 \\ {x}^{2} + 26x - 27 = 0$

Solving this quadratic equation,

${x}^{2} + 27x - x - 27 \\ = x(x + 27) - (x + 27) \\ = (x + 27)(x - 1)$

The roots of this equation will give values of x.

So x must be either -27 or 1 and since options provide only one of them we have option (a) as the correct one.