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Step-by-step explanation:
To prove : PR² = 2PQ²
Given : PQR is an isosceles right triangle with ∠Q = 90°.
In the given triangle ,
∠Q = 90°
PR is the hypotenuse. And, QR = PQ as the triangle is isosceles.
By the Pythagoras theorem,
(Hypotenuse)² = (Opp. Side)² + (Adj.side)²
PR² = PQ² + QR²
PR² = PQ² + PQ²
PR² = 2PQ²
Therefore, It is proved that PR² = 2PQ²
hope it's helpful.....
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