Question

pl tell the answer of this question​

Answer 1

AnsWer :

Distance = 10 m

And Displacement = √18 m.

Concepts Required :

• Distance - Total distance cover by body, it said to be Distance.
• Displacement - Shortest distance cover by body intial to final point, it said to be Displacement.

Solution :

For Distance,

Turtle crawls 5m North, then 3m East and then 2m south.

Sum of all distance cover by Turtle.

$\tt\dashrightarrow 5 + 2 + 3 = 10 \: m.$

For Displacement,

• We have 90° with angle DEC.
• Apply Pythagoras theorem.

$\tt \dashrightarrow {H }^{2} ={ P }^{2} +{ B }^{2} .$

• P = 3m.
• B = 3m.
• H = ?.

$\tt\dashrightarrow {h}^{2} = {(3)}^{2} + {(3)}^{2} .$

$\tt\dashrightarrow {h}^{2} = 9 + 9.$

$\tt\dashrightarrow{ h }^{2} = 18.$

$\tt\dashrightarrow h = \sqrt{18} \: m.$

Therefore, the value of Distance cover by Turtle be 10 m and Displacement be √18 m.

Answer 2

We know,

Displacement is the shortest length between the initial and the final point.

∴ Shortest length = AD

Here, in △AED,

AD² = AE² + DE² {Pythagoras theorem}

(∵ ∠AED forms 90°)

And, AE = AB - BE = (5 - 2) m = 3 m

∴ AD = √[(3 m)² + (3 m)²] = √9 + 9 m² = √18 m²

⇒ AD = (3√2) m.

∴ The displacement is (3√2) m.