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Q. Find the compound interest on ₹ 25,000 at the rate of 12 % per annum for 3 years( as told ).
Given, principal = ₹ 25,000
rate = 12 % p.a , time = 3 yrs
Find the amount :
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amount = p [ 1 + ( r/100 ) ]^t
amount = 25,000 [ 1 + ( 12/ 100) ]^3
amount = 25000( 112/100 )^3
amount = 25000( 56/50)^3
= 25000 × 56/ 50 × 56/ 50 × 56/ 50
=( 25 × 56 × 56 × 56 ) / 125
= (56 × 56 × 56 ) / 5
= 175616 ÷ 5 = ₹35123.2
Find the compound interest :
---------------------------------
C.I = amount - principal
C.I = ₹35123.2 - 25,000 = ₹10,123.2
therefore,
the compound interest = ₹10,123.2
Answer : C.I = ₹10,123.2
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Given, principal = ₹ 25,000
rate = 12 % p.a , time = 3 yrs
Find the amount :
-----------------------
amount = p [ 1 + ( r/100 ) ]^t
amount = 25,000 [ 1 + ( 12/ 100) ]^3
amount = 25000( 112/100 )^3
amount = 25000( 56/50)^3
= 25000 × 56/ 50 × 56/ 50 × 56/ 50
=( 25 × 56 × 56 × 56 ) / 125
= (56 × 56 × 56 ) / 5
= 175616 ÷ 5 = ₹35123.2
Find the compound interest :
---------------------------------
C.I = amount - principal
C.I = ₹35123.2 - 25,000 = ₹10,123.2
therefore,
the compound interest = ₹10,123.2
Answer : C.I = ₹10,123.2
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