pla answer tomorrow are my exams
Q9.
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in □ABCD
angle A + angle B = 180° ---- angles in pair are supplementary in a □
A:B:C:D = 3:7:6:4
let the common multiple be x
angle A= 3x
angle B= 7x
3x + 7x = 180
10x = 180
x=18°
angle A = 3x= 3×18= 54°
angle B = 7x = 7×18=126°
angle C = 6x = 6×18=108°
angle D = 4x = 4×18=72°
as all angles are not equal and only addition of paired angles are supplementary it is an trapezium
PLEASE MARK AS BRANILIST PLEASE
angle A + angle B = 180° ---- angles in pair are supplementary in a □
A:B:C:D = 3:7:6:4
let the common multiple be x
angle A= 3x
angle B= 7x
3x + 7x = 180
10x = 180
x=18°
angle A = 3x= 3×18= 54°
angle B = 7x = 7×18=126°
angle C = 6x = 6×18=108°
angle D = 4x = 4×18=72°
as all angles are not equal and only addition of paired angles are supplementary it is an trapezium
PLEASE MARK AS BRANILIST PLEASE
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