place A and B are 30km apart and they are on a straight road hamid travel from A go B
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21
hola!
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Let the speed of Joseph = x km/h
Let the speed of Hamid = y km/h
Case 1. ]
Approaching one another, combined speed = (x+y)km/h
Time taken to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ [ i ]
Case 2. ]
When moving in opposite direction, combined speed = (x-y)km/h
Time taken for Hamid to catch up = 30/(x-y) = 3
x-y = 10 ----[ ii ]
Solving [ i ] and [ ii ] simultaneously,
x = 40
n'
y = 50
Hence,
Speed of Joseph = x = 40km/h
Speed of Hamid = y = 50km/h
_______________________
Hope it helps! :D
_______________________
Let the speed of Joseph = x km/h
Let the speed of Hamid = y km/h
Case 1. ]
Approaching one another, combined speed = (x+y)km/h
Time taken to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ [ i ]
Case 2. ]
When moving in opposite direction, combined speed = (x-y)km/h
Time taken for Hamid to catch up = 30/(x-y) = 3
x-y = 10 ----[ ii ]
Solving [ i ] and [ ii ] simultaneously,
x = 40
n'
y = 50
Hence,
Speed of Joseph = x = 40km/h
Speed of Hamid = y = 50km/h
_______________________
Hope it helps! :D
Answered by
1
Answer:
Let the speed of Hamid and Joseph be x km/h and y km/h respectively.
according to given condition
x/3+y/3=30---------.1. because 20 mins in hrs be like 1/3 hrs so distance=speed*time
3x-3y=3--------2
by solving these 2 simultaneous equations you will get your answers.
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