Place the digits 1, 2, 3, 4, 5, 6 in the circles in (See opposite figure) so that the sum of the three numbers on each side of the triangle is 12.
Answers
Given : A triangle with 3 circles ( one on each vertex) and one circle on each side of a triangle
To Find : Place the digits 1, 2, 3, 4, 5, 6 in the circles in so that the sum of the three numbers on each side of the triangle is 12.
Solution:
A
B C
D E F
sum of the three numbers on each side of the triangle is 12.
Hence A + B + D = 12
A + C + F = 12
D + E + F = 12
Adding all
A + B + C + D + E + F + (A + D + F) = 36
A + B + C + D + E + F = 21
21 + (A + D + F) = 36
=> A + D + F = 15
6 + 5 + 4 = 15
Hence 6 , 5 and 4 will be on vertices of triangle
Rest 3 Digits to be filled to get sum 12
6
1 2
5 3 4
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