PLACE26SHEEPIN4PENS SOTHATTHEREISAN ODD NUMBER OF SHEEP INEACH PEN
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SIMPLE DIVIDE 26 IN TO ADDTION OF ODD NUMBERS
EX: 5+7+7+7
5 SHEEP IN 1ST PEN
7 SHEEP IN 2ND PEN
7 SHEEP IN 3RD PEN
7 SHEEP IN 4TH PEN
EX: 5+7+7+7
5 SHEEP IN 1ST PEN
7 SHEEP IN 2ND PEN
7 SHEEP IN 3RD PEN
7 SHEEP IN 4TH PEN
Answered by
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first
divide 26 with 4
we get 6·5
so first we can have 6 sheep in all pens with 2 left
first:6+3
second:6-3
third:6-1
fourth:6+1
now,
first:9
second:3
third:5
fourth:7
remaining two can be added to any of the pen
now,
first:9
second:5
third:5
fourth:7
i added the 2 to second pen
so, here's the answer
divide 26 with 4
we get 6·5
so first we can have 6 sheep in all pens with 2 left
first:6+3
second:6-3
third:6-1
fourth:6+1
now,
first:9
second:3
third:5
fourth:7
remaining two can be added to any of the pen
now,
first:9
second:5
third:5
fourth:7
i added the 2 to second pen
so, here's the answer
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