places A and B are 30 km apart and they are on a straight road. Hamid travels from A to B on bike.At the same time Joseph starts from B on bike towards A. They meet each other after 20 minutes.If Joseph would have started from B at same time but in the opposite direction (instead of towards A) Hamid would have caught him after 3hours. Find the speed of Hamid and Joseph
Answers
Please refer the above photograph for the used process
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Step-by-step explanation:
Let the speeds of Hamid and Joseph be x km/hr andy km/hr respectively. Distance travelled by Hamid in 20 minutes i.e. (1/3)hrs = (1/3)x km Distance travelled by Joseph in (1/3)hrs = (1/3)y km According to the first condition, (1/3)x = (1/3)y = 30 x + y = 90 …(i) [Multiplying both sides by 3] Distance travelled by Hamid in 3 hrs = 3x km Distance travelled by Joseph in 3 hrs = 3y km According to the second condition, 3x – 3y = 30 x – y = 10 … (ii) [Dividing both sides by 3 ] Adding equations (i) and (ii), we get x + y = 90 + x - y = 10 / 2x = 100 ∴ x = 100/2 = 50 Substituting x = 50 in equation (i), we get 50 + y = 90 ∴ y= 90 - 50 = 40 ∴ The speeds of Hamid and Joseph 50 km/hr and 40 km/hr respectively.Read more on Sarthaks.com - https://www.sarthaks.com/842995/solve-the-following-word-problems-places-and-are-km-apart-and-they-are-straight-road-hamid