Places A and B are 30 km apart and they are on a straight road. Hamid travels from A to B on bike. At the same time Joseph starts from B on bike, travels towards A. They meet each other after 20 minutes. If Joseph would have started from B at the same time but in the opposite direction (instead of towards A) Hamid would have caught him after 3 hours. Find the speed of Hamid and Joseph. Solve the word problem
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Hi ,
Distance between A and B = 30km
Let the speed of Hamid = x kmph
speed of Joseph = y kmph
i ) Relative speed of them when they
are traveling
in opposite direction = ( x + y )kmph
time taken to meet
each other = d/relative speed
20mi = 30/( x + y )
(20/60 ) hr = 30/( x + y )
1/3 = 30/( x + y )
x + y = 90 ---( 1 )
ii ) Relative speed if they travel in the
same direction = ( x - y ) kmph
time = d/( relative speed )
3 = 30/( x - y)
x - y = 10 ---( 2 )
add equations ( 1 ) and ( 2 ) , we get
2x = 100
x = 50
put x = 50 in equation ( 1 ) , we get
50 + y = 90
y = 40
Therefore ,
Speed of Hamid = x = 50kmph
Speed of Joseph = y = 40 kmph
I hope this helps you.
: )
Distance between A and B = 30km
Let the speed of Hamid = x kmph
speed of Joseph = y kmph
i ) Relative speed of them when they
are traveling
in opposite direction = ( x + y )kmph
time taken to meet
each other = d/relative speed
20mi = 30/( x + y )
(20/60 ) hr = 30/( x + y )
1/3 = 30/( x + y )
x + y = 90 ---( 1 )
ii ) Relative speed if they travel in the
same direction = ( x - y ) kmph
time = d/( relative speed )
3 = 30/( x - y)
x - y = 10 ---( 2 )
add equations ( 1 ) and ( 2 ) , we get
2x = 100
x = 50
put x = 50 in equation ( 1 ) , we get
50 + y = 90
y = 40
Therefore ,
Speed of Hamid = x = 50kmph
Speed of Joseph = y = 40 kmph
I hope this helps you.
: )
Tanishkamoon:
Thanku & useful solution
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