Places A and B are 30 km apart and they are on a straight road. H
from A to B on bike. At the same time Joseph starts from B
on bike, travels towards A. They meet each other after 20
minutes. If Joseph would have started from B at the same
time but in the opposite direction (instead of towards A)
Hamid would have caught him after 3 hours. Find the speed
of Hamid and Joseph.
Answers
Answered by
0
Answer:
R.E.F image
Let speed of Hamid = H km/hr
Let speed of Joseph = J. km/hr
Then when they travel in opposite direction
x=H×31
30−x=J×31
⇒30−H/3=J/3
⇒[J=90−H]...(i)
When same direction & meet at c
D=J×3
30+D=3H
[30+3J=3H]...(ii)
On solving eqn (i) & (ii) we get
[H = 50 km/br & J = 40 km/hr]
Similar questions