Math, asked by priyanshi1704, 11 months ago

. Places A and B are 80 km apart from each other on a highway. A car starts from A and another from B at
the same time. If they move in same direction they meet in 8 hrs and if they move in opposite direction they
meet in 1hr.20minutes. find speed of the car.

Answers

Answered by Anonymous
8

♕hello

answer:

⚘Let the speed of the first car which

starts from A = x km /hr

Speed of the second car which starts

from B = y km / hr

We know that,

______________________

Time = distance / speed

______________________

Distance between two places A and

B are 80km

d = 80 km

i ) if the cars move in same direction

Relative speed of them = ( x + y )

km/hr

Time = 8hr

d = 80km

8 = 80 / ( x + y )

x + y = 80 / 8

x + y = 10 ------( 1 )

ii ) if two cars moving opposite

direction,

Relative speed = ( x - y ) km / hr

Time = 1 hr 20 minutes

= ( 1 + 20 / 60 ) hr

= ( 80/60)

= 4/3 hr

d = 80km

4/3 = 80 / ( x -y )

x -y = ( 80 × 3 ) / 4

x - y = 60-----( 2 )

Add ( 1 ) and ( 2 ) , we get

2x = 70

x = 35

Put x = 35 in ( 1 ) we get ,

y = 25

Therefore ,

Speed of the first car = x = 35km/hr

Speed of the second car = 25km /hr

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Answered by pitalemadhvi
0

Answer:

Step-by-step explanation:

We can use the formula speed= distance/time so, we can keep the value as:

Distance =80 km

Time = 1hr20 mins

S= D/T

= 80/80 = 1km/min

80 mins because 1hr20 min was converted into mins.

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