Places A and B are 80 km apart on a highway. One car starts from A and another from B at the same time if the car travel in the same direction at different speeds they meet in 4 hours if they travel towards each other they meet in 1 hour what are the speed of the two cars.
Answers
Answer:
S1 =50, S2 =30
Step-by-step explanation:
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Step-by-step explanation:
=>let the speed of the first car be x km/hr and
=>speed of second car be y km/hr
=time 8 hr
=>distance traveled by first car=AC and
=>distance traveled by second car=BC
=>difference of distance traveled=AC-BC
=(AB+BC)-BC
=AB
=80 km
therefore,
distance traveled by first car - distance traveled by second car = 80 km
=>distance = speed × time
=4x-4y=80
=4(x-y)=80
=x-y=80 / 4
=x-y=20 ----------(1)
time=1 hr
distance traveled by first car=AC
distance traveled by second car=BC
therefore,
distance traveled by first car + distance traveled by second car =80
distance=speed×time
=>1x+1y=80
=>1(x+y)=80
=>x+y=80 ........(2)
thus,our equations are
x-y=20 ......(1)
x+y=80 .......(2)
adding (1) and (2)
=>(x-y)+(x+y)=20+80
=>2x=100
=>x=50
putting value of x in (2)
=>x+y=80
=>50+y=80
=>y=80-50
=>y=30
so
speed of first car =x=50 km/hr
speed of second car =y=30 km/hr
hope it helps mark as brilliant.