Places A and B are 80km apart from each other on highway. A car starts from A and another from B at the same time. If they move in same direction they meet in 8 hours and if they move towards each other they meet 1 hour 20 minute.Find the speed of the cars.
Answers
Answer:
Let the speed of car starting from A be 'x' km/h and speed of car starting from B be 'y' km/h.
Total distance=80 km
Also 1 hour 20 mins= 4/3 hour
As per given condition, When car moves in same direction,
Distance travelled by y= 8y km
Distance travelled by x= 8x= 80+8y
Now, Equation formed is 8x=80+8y
=> 8x-8y=80
=> x-y=10 ----(1)
Similarly, For opposite direction,
Distance travelled by x= (4/3)x
Distance travelled by y= (4/3) y
Also total distance covered= 4/3*x+4/3y
=> 80= 4x+4y/3
=> 240= 4x+4y
=> 60=x+y ----(2)
Solving Equation (1) and (2)
60=x+y ----(2)
x-y=10 ----(1)
=> x= 10+y ----(3)
Substituting the value of (3) in (2) we get,
60= 10+y+y
=> 60-10=2y
=> 50=2y
=> 25=y
Also, x=10+y=> x= 10+25=> x=35
Therefore Speed of car starting from A is 35km/h
Speed of car starting from B is 25km/h
Answer:
Speed of Car A and B are 35 km / hr and 25 km / hr respectively.
Step-by-step explanation:
Let the speed of car at A is x km / hr and at B is y km / hr
Case 1.
8 x - 8 y = 80
x - y = 10
x = 10 + y ... ( i )
Case 2.
4 / 3 x + 4 / 3 y = 80
x + y = 60
x = 60 - y ... ( ii )
From ( i ) and ( ii )
10 + y = 60 - y
y = 25
Putting value of y in ( i )
x = 10 + 25
x = 35 .