Question

plaease solve the following arathmetic progression sum​

Answer 1

Answer:

hello...

a=32

d=a2-a3 =36-32=4

sn=2000

n=?

sn=a+(n-1)d

2000=32+(n-1)4

2000-32=(n-1)4

1968=(n-1)4

1968/4=(n-1)

492=n-1

493=n

n=493

so shubham will save 2000 in 493 month

Answer 2

Hope it’s correct if any mistake pls do inform