Plaese give me solution from photo
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1
Answer:
Correct option is
C
3 : 4 : 5
Let a−d,a,a+d be the sides of Right angled triangles, which are in AP with first term a and common difference d.
∴(a+d)^2=a^2+(a−d)^2 (∵ of right angled triangle.)
⇒a^2+2ad+d 2 =a^2+a^2−2ad+d^2
⇒a^2−4ad=0
⇒a(a−4d)=0
⇒a=0,4d
But, a=0 is not possible.
Therefore, a=4d.
Hence side are 3d,4d,5d.
i.e they are in ratio 3:4:5
Answered by
0
Step-by-step explanation:
so your option c is correct i.e 3:4:5 .
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