Question

Plan two different routes for the conversation of benzyl chloride into phenylethanoic acid.

Answer 1

Two different ways of getting phenylethanoic acid from benzylchloride are as follows;

1. You should consider treating benzylchloride with KCN, potassium cyanide to get benzyl nitrile(C6H5CH2CN).

Then this is followed by hydrolysis with dilute, hydrochloric acid, HCl  and you will get phenylethanoic acid.

Please consider that conversion and I hope it is helpful.

Answer 2

Answer:

ANSWER

We know, p(x)=[g(x)×q(x)]+r(x)

∴p(x)−r(x)=g(x)×q(x)

∴p(x)+{−r(x)}=g(x)×q(x)

It is clear that RHS is divisible by g(x). ∴LHS is also divisible by g(x)

Thus, if we add −r(x) to p(x), then the resulting polynomial is divisible by g(x).

Let us divide p(x)=x

4

+2x

3

−2x

2

+x−1 by g(x)=x

2

+2x−3 to find the remainder r(x).

∴r(x)=−x+2⇒{−r(x)}=x−2

Hence, we should add (x−2) to p(x)=x

4

+2x

3

−2x

2

+x−1 so that the resulting polynomial is exactly divisible by x

2

+2x−3.