Question

planar SP3 hybridised molecule having same surrounding atoms has 18 % character in a bond the percent P character in lone pair of central atom is​

Answer 1

Answer:

If the planar SP3 hybridized molecule having same surrounding atoms has 18 % character in a bond the percent P character in lone pair of central atom is The percent p character may be 82%

Explanation:

What is the percentage of s and p character in SP2/SP3 hybrid orbital?

The percentage of s and p character in sp, sp2 and sp3 hybrid orbital is, Sp : s characteristic 50% and p characteristic 50%, Sp2: s characteristic 33.33% and p characteristic 66.66%, Sp3: s characteristic 25% and p characteristic 75%.

What is sp3 hybridization in chemistry?

sp 3 Hybridization. When one ‘s’ orbital and 3 ‘p’ orbitals belonging to the same shell of an atom mix together to form four new equivalent orbital, the type of hybridization is called a tetrahedral hybridization or sp 3. The new orbitals formed are called sp 3 hybrid orbitals.

AS, the hybridization is explained you can check the below image to know more about this .

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Answer 2

Answer: The correct answer is 82 percent.  

SP3: If planar SP3 hybridized molecule have same surrounding atoms with 18 percent character in a bond, The percent of P character in lone pair of the central atom is 82 percent.

SP2: It's worth noting that hybridization goes by a few other names, including trigonal hybridization. This process creates a new hybrid orbital, sp2, by combining one s orbital with two p orbitals of the same energy. Trigonal symmetry, which is 120 degrees, allowed for the formation of a mixture of s and p orbitals.

Explanation:

• SP3 Hybridization: The combining of one 2s-orbital and three 2p-orbitals to produce four hybrid orbitals with comparable properties, to get sp3 hybridization combination of one s and three p orbitals are required.
• The percentages of the s and p characteristics in the sp, sp2, and sp3 hybrid orbitals are as follows:
• the sp hybrid orbital has 50% of the s characteristics and 50% of the p characteristics because no. of s and p orbitals are same so characteristics are distributed equally.
• the sp2 hybrid orbital has 33.33% of the s characteristics and 66.66% of the p characteristics, because no. of s and p orbitals are 1 and 2 respectively, Therefore one third of s characteristics and two third of p characteristics will be observed.
• the sp3 hybrid orbital has 25% of the s characteristics and 75% of the p characteristics, because s and p orbitals are 1 and 3 respectively, therefore one fourth of s characteristics and three fourth of p characteristics are observed.  

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