Question

plane diffraction grating has the value of grating constant equal to 15x10^-4 cm. Calculate the position of the third order maximum for ∆ = 2.4x10^-4
cm.​

Answer 1

Answer:

it 5.7

Explanation: bc it 5.7

Answer 2

Given:

Value of grating constant = 15 x $10^{4}$ per cm

Order of diffraction grating = 3

Wavelength of light = 2.4 x  $10^{-4}$ cm

to find:

Position of third-order maximum.

Solution:

We will use the grating formula to find the angle at which the

third-order maximum will be formed.

d sin∅ = mΔ

where,

d = distance between slits

m = order of maximum

∅ = position at which maximum is formed

Δ = wavelength of light used

Now, we know that

d = 1/ grating constant

grating constant = 15 x $10^{4}$ lines per cm

therefore, d = $\frac{1 }{150000}$ cm =6.66 x $10^{-8}$ m

also,

Δ  = 2.4 x  $10^{-4}$  = 2.4 x  $10^{-6}$ m

Now using all the values in the formula

6.66 x $10^{-8}$  x sin∅ = 3 x 2.4 x  $10^{-6}$

sin∅ = 108

This value of sin∅ = 108 is not possible, hence a third-order maximum will not be formed.