Question

Plane x + 2y = 10 carries uniform surface charge density, 2nc/m2. Resulting
electric field at a point near to the plane makes an angle 'O' with X-axis, and
A. Find the value of A. [Here A and B are integers in their simplest form]
sin 8 =
VB​

Answer 1

Answer:

4

Explanation:

Field will be perpendicular to the plane.

Since the slope of x+2y=10 is -1/2

Slope of field will be 2

So, tanθ = 2

⇒ sinθ=$\sqrt4/ \sqrt{5$

∴ A=4,B=5

Answer 2

Answer:

The value of $A=4,B=5$

Explanation:

We are given that plane $x + 2y = 10$ carries uniform surface charge density.

Resulting electric field at a point near to the plane makes an angle 'O' with X-axis.

sinθ=$\frac{\sqrt{A} }{\sqrt{B} }$

We need to determine A and B.

It is given that field will be perpendicular to the plane.

Slope of given line $x+2y=10$ is $m=-1/2$

Hence, slope of field is $2$.

It means tanθ = $2$

Converting we get,

sinθ=$\frac{\sqrt{4} }{\sqrt{5} }$

Hence, $A=4,B=5$

#SPJ2