Question

plase reply me fast​

Answer 1

Answer:

let where all the points meet be o.

If EF is a straight line,

then,

<EOC+<COA+<AOF=180°

30°+<COA+90°=180°

<COA=180°-120°

<COA=60°.

if CD is a straight line,

then,

<COA+<AOF+<FOD=180°

<FOD=180°-150°

<FOD=30°.

if AB is a straight line.

then,

<AOF+<FOD+<DOB=180°

90°+30°+3y=180°

3y=180°-120°

y=60°/3

y=20°.

<DOB=3y

DOB=3y<DOB=3×20°

DOB=3y<DOB=3×20°<DOB=60°.

hence, y=20°.

I hope it will help full to you.

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