Math, asked by radhikaa21, 1 year ago

plastic box of 1.25 m long,1.05 m wide,75 depth its to be open in top ignore thickness of plastic sheet determine area of sheet required for making box also find cost of sheet isq.m= 20

Answers

Answered by AiyraBaig09
3

Solution (i)

 Length of open plastic box =l=1.5 m

 Breadth of open plastic box =b=1.25 m

 Height of open plastic box =h=75 cm =75/100=0.75 m

 The area of the sheet required for making the open plastic box =lb+2bh+2hl  

(Because it is open from the top)

 =(1.5)(1.25)+2(1.25)(0.75)+2(0.75)(1.5)

=1.875+1.875+2.25

=6.00  m2

 

 

Solution (ii)

1 m2 of sheet costs Rs 20

 6.00 m2 of sheet would cost =6.00×20= Rs 120


radhikaa21: l=1 25m
AiyraBaig09: Sorry
AiyraBaig09: Solution (i)
Length of open plastic box =l=1.25 m
Breadth of open plastic box =b=1.05 m
Height of open plastic box =h=75 cm =75/100=0.75 m
The area of the sheet required for making the open plastic box =lb+2bh+2hl
(Because it is open from the top)
=(1.25)(1.05)+2(1.05)(0.75)+2(0.75)(1.25)
=1.3125+1.575+1.875
=4.7625 m2


Solution (ii)
1 m2 of sheet costs Rs 20
4.7625 m2 of sheet would cost =6.00×20= Rs 95.25
radhikaa21: thank you
AiyraBaig09: : )
Answered by MissAngry
2

Question :-

A plastic box 1.5 m long, 1.25 m wide and 65 cm deep is to be made. It is opened at the top. Ignoring the thickness of the plastic sheet, determine

(i) The area of the sheet required for making the box.

(ii) The cost of sheet for it, if a sheet measuring 1m2 costs ₹20.

Answer :-

(i) Here, length (l) = 1.5 m, bread th(b) = 1 .25 m

and height (h) = 65 cm = 65/100 m = 0.65 m

∵ It is open from the top.

∴ Its surface area

= [Lateral surface area] + [Base area]

= [2(1 + b)h] + [lb]

= [2(1.50 + 1.25)0.65] m2 + [1.50 x 1.25] m2

= [2 x 2.75 x 0.65] m2 + [1.875] m2

= 3.575 m2+ 1.875 m2 = 5.45 m2

∴ Area of the sheet required for making the box = 5.45 m2

(ii) Cost of 1 m2 sheet = Rs. 20

Cost of 5.45 m2 sheet = Rs. (20 x 5.45)

= Rs. 109

Hence, cost of the required sheet = Rs. 109

Plz mrk as brainliest ❤

Similar questions