Question

 platinum wire has resistance of 2.5Ω at 0°C. If its temperature coefficient is of resistance is 4×10⁻³/°C, The resistance of wire at 70°C is ​

Answer 1

Answer:

Explanation:

R = Re (1+a(T-Te))

where, Re is the resistance of a conductor at a reference temperature of Te

and a=temperature coefficient of resistance so,

Re = 2.52

Te = 0

T = 80

a =  4 * 10^3

so, R = 2.52(1 + 4000*70)

       = 2.52 * 280001

       = 700002.52