Question

player A has probability 3/5 of winning a game pf chess with player B if they play 4 games find the probability that player A wins at least 3 games​

Answer 1

Answer:

BTS ARMY here

Step-by-step explanation:

Let x be the number of games that ‘A’ wins, is a Binomial variate with parameters

n = 4, p = 3535

∴ q = 1 – p = 2525

The p.m.f is – P(x) = ncxpxqn – x ;

x = 0,1,2, …… n

(a) p (A wins exactly one game)

= 4 × 0.6 × 0.064 = 0.1536.

(b) p (A wins atleast 3 games)

= p(x ≥ 3)

= p (x = 3) + p (x = 4)

= 4 × 0.216 × 0.4 + 1 × 0.1296 x 1

= 0.3456 + 0.1296

= 0.4752.

Mark me as brainlist

Answer 2

Answer:

Mark the above ans as brainliest !!