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$n2852 + y227 |346 \geqslant | \times \frac{?}{?}$
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Answer 1

Answer:

If the remainder is same in each case and remainder is not given, HCF of the differences of the numbers is the required largest number

9997 - 7654 = 2343

9997 - 8506 = 1491

8506 - 7654 = 852

Hence, the greatest number which divides 7654, 8506 and 9997 and leaves same remainder

= HCF of 2343, 1491, 852

= 213

Now we need to find out the common remainder.

Take any of the given numbers from 7654, 8506 and 9997, say 7654

7654 ÷ 213 = 35, remainder = 199

Answer 2

Answer:

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• Answer in the attachment!!

Hope this helps you!!