playing urgent solve Q. 24 2nd part and Q. 28 fast
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24. 2nd part
Given time needed by the minutes hand show (t2/4) – 3 Hence the quadratic equation becomes, (t2/4) – 3 = 60 – t (t2– 12)/4 = 60 – t (t2 – 12) = 240 – 4 t t2 – 12 – 240 + 4 t = 0 t2 + 4t – 252 = 0 t2 + 18t – 14t – 252 = 0 t(t + 18) – 14(t + 18) = 0 (t + 18)(t – 14) = 0 (t + 18) = 0 or (t – 14) = 0∴ t = - 18 or t = 14 Since t cannot be negative, t = 14
number 28 is done in the above photographs
I have written it by myself please mark it as the brainllist if it will help you
please say thanks for this answer too
Given time needed by the minutes hand show (t2/4) – 3 Hence the quadratic equation becomes, (t2/4) – 3 = 60 – t (t2– 12)/4 = 60 – t (t2 – 12) = 240 – 4 t t2 – 12 – 240 + 4 t = 0 t2 + 4t – 252 = 0 t2 + 18t – 14t – 252 = 0 t(t + 18) – 14(t + 18) = 0 (t + 18)(t – 14) = 0 (t + 18) = 0 or (t – 14) = 0∴ t = - 18 or t = 14 Since t cannot be negative, t = 14
number 28 is done in the above photographs
I have written it by myself please mark it as the brainllist if it will help you
please say thanks for this answer too
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tanishq972003:
we need two answers for this.
hey friend plz once gave equation of 28 here pls I don't understand I solve equation pls.
we need two answers for this
Abe yaar kitni baar batao we need answer of two person then option appears
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