Question

playing with number
If a' 'b' and are numbers between 0 and 9, find their value in the
following
100a + 40 + 8 = 600 + 48
b =
700 + 10b +C = 800 – 75
a =
100a + 60 + C = 300 + 50 + 17
b = - =
. 900 + 10b + c = 1000 - 8
a =
.b=
• 100a + 10b + 9 is a largest 3 digit number so
• 100a+10b+ C = 300 + 120
a = b = __
• 100a+10b + c = 1000 - 347
a= b =
• 100a + 10b + c = 500 + 2 + 8
a =
b=
• 100a+10b + c = 200 +227 +31
a =
b= =
. 100a + 10b + c = (40 x 3) + (11 x 7) a= _ , b = _
• 100a + 10b + c = (1000 + 4) - 162 a :
b
b
C=​

Answer 1

Answer:

b

Step-by-step explanation:

b is answering of the question