Playing with numbers find the largest no which exactly divides 280 and 1245 learing remainder 4 and 3
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Your answer
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Given that : -
A number divides 280 and 1245 leaving remainders 4 and 3.
Find the number?
Now,
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As the number leaves remainders 4 and 3.
That means,
The number divides (280 - 4) = 276 and (1245 - 3) = 1242 perfectly.
Then,
The number = HCF of 276 and 1242
Now,
276 = 2² × 3 × 23 and 1242 = 2 × 3³ × 23
HCF = 2 × 3 × 23 = 138
Therefore ,
The number is 138.
HOPE IT HELPS
----------------
Your answer
------------------
Given that : -
A number divides 280 and 1245 leaving remainders 4 and 3.
Find the number?
Now,
---------
As the number leaves remainders 4 and 3.
That means,
The number divides (280 - 4) = 276 and (1245 - 3) = 1242 perfectly.
Then,
The number = HCF of 276 and 1242
Now,
276 = 2² × 3 × 23 and 1242 = 2 × 3³ × 23
HCF = 2 × 3 × 23 = 138
Therefore ,
The number is 138.
HOPE IT HELPS
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