Question

ple
Find acceleration of 4 kg & 6 kg in the given scenario.
5 ms-2

Answer 1

Explanation:

11th

Physics

Laws of Motion

Application of Newton's Laws of Motion

Two masses of 6 Kg and 4 Kg...

PHYSICS

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Asked on December 26, 2019 by

Veronica Tbhat

Two masses of 6 Kg and 4 Kg are connected to the two ends of a light inextensible string that goes over a frictionless pulley. Find the acceleration of the masses and the tension in the string when the masses are released. Take g=10ms

−2

.

HARD

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ANSWER

Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up

So the equation of net force on 6kg is given as

6×10−T=6a

equation of net force on 4kg is given as

T−4×10=4a

now add the above two equations

6×10−(4×10)=(6+4)×a

60 - 40 = 10a

a = 2m/s

2

So 6 kg will accelerate downwards while 4 kg will accelerate upwards

with acceleration 2 m/s

2

now in order to find the tension force

T−4×10=4×2

T = 48N

So the tension in the string is 48 N

Answer 2

$\huge\red{Answer}$

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☆☞ [ Verified answer ]☜☆

Assuming negligible friction

As mass of the system=1+4 kg=5kg.

As F=m*a

Thus acceleration of system=15/5=3m/s^2

As tension force is only force acting on 1 kg. block bringing an acceleration of 3 m/s^2

As Fm**acc

T=1kg.*3m/s^2=3 N

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