Question

pleae answer it fast

Answer 1

Given

LHS = cos^2A - sin^2A = tan^2B

           cos^2A - (1 - cos^2A) = sec^2B - 1

          cos^2A - 1 + cos^2A = sec^2B - 1

          2cos^2A - 1 = sec^2B - 1

          2cos^2A = sec^2B - 1 + 1

          2cos^2A = sec^2B 

          2/sec^2A = 1/cos^2B

          2cos^2B = sec^2A   ------------------ (1)

           



Now,

RHS = cos^2B - sin^2B

        = cos^2B - (1 - cos^2B)

        = cos^2B - 1 + cos^2B

        = 2cos^2B - 1

        = sec^2A - 1

        = tan^2A.


LHS = RHS.



Hope this helps!

Answer 2

Hi,

Please see the attached file!

Thanks