pleaee answer this question .here after IF there is X
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HELLO DEAR,
X = 1/(√5 - 2)
=> 1/(√5 - 2) × (√5 + 2)/(√5 + 2)
=> (√5 + 2)/(5 - 4)
=> X = (√5 + 2)
on squaring both side
we get,
x² = 5 + 4 + 4√5
=> x² = (9 + 4√5)
NOW,
x³ - 3x² - 5x + 3
=> x(x² - 3x - 5) + 3
=> (√5 + 2)(9 + 4√5 - 3 - 5) + 3
=> (9√5 + 18 + 20 + 8√5 - 5√5 - 10)
=> 12√5 + 28
=> 12√5 + 28 + 3
=> (12√5 + 31)
I HOPE ITS HELP YOU DEAR,
THANKS
X = 1/(√5 - 2)
=> 1/(√5 - 2) × (√5 + 2)/(√5 + 2)
=> (√5 + 2)/(5 - 4)
=> X = (√5 + 2)
on squaring both side
we get,
x² = 5 + 4 + 4√5
=> x² = (9 + 4√5)
NOW,
x³ - 3x² - 5x + 3
=> x(x² - 3x - 5) + 3
=> (√5 + 2)(9 + 4√5 - 3 - 5) + 3
=> (9√5 + 18 + 20 + 8√5 - 5√5 - 10)
=> 12√5 + 28
=> 12√5 + 28 + 3
=> (12√5 + 31)
I HOPE ITS HELP YOU DEAR,
THANKS
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