Math, asked by ak7654586, 6 months ago

pleas ans me maths pleas me ​

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Answered by Thenavi
0

Step-by-step explanation:

i. 73101

7+3+1+0+1=1

12 is divisible by 3

Therefore, 73101 is divisible by 3

ii. 16422

1+6+4+2+2=15

15 is divisible by 3

Therefore, 16422 is divisible by 3

iii. 74912

7+4+9+1+2=23

23 is not divisible by 3

Therefore, 74912 is not divisible by 3

Answered by sikharmalkam
0

Solution:

(1) Sum of all the digits of 73101=7+3+1+0+1=12

which is divisible by 3

Hence, the number 73101 is divisible by 3.

(2)Sum of all the digits of 16422=1+6+4+2+2=15

which is divisible by 3

Hence the number 16422 is also divisible by 3.

(3)Sum of all the digits of the number 74912=7+4+9+1+2=23

which is not divisible by 3

Hence, the number 74912 is not divisible by 3.

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