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f max = maximum frictional force = (N)(mu)
Here,
W = N = (50)(10) = 500 N
mu = 0.1 (given)
So, max friction = 50N
But, here, horizontal force applied is 15 N
Hence, frictional force will also be 15 N to maintain equilibrium.
Here,
W = N = (50)(10) = 500 N
mu = 0.1 (given)
So, max friction = 50N
But, here, horizontal force applied is 15 N
Hence, frictional force will also be 15 N to maintain equilibrium.
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