pleas answer this by using identiy
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Hi ,
x - 1/x = 3 + 2√2 -----( 1 )
***********************
We know the algebraic identity ,
a³ - b³ - 3ab( a - b ) = ( a - b )³
Or
a³ - b³ = ( a - b )³ + 3ab( a - b )
************************
x³ - 1/x³ = ( x - 1/x )³ + 3×x × 1/x(x - 1/x )
= ( x - 1/x )³ + 3( x - 1/x )
= ( 3 + 2√2 )³ + 3( 3 + 2√2 )
= ( 3 + 2√2 ) [ (3 + 2√2 )² + 3 ]
= ( 3 + 2√2 ) [ 9 + 8 + 12√2 + 3 ]
= ( 3 + 2√2 ) [ 20 + 12√2 ]
= 60 + 36√2+ 40√2 + 48
= 108 + 76√2
I hope this helps you.
: )
x - 1/x = 3 + 2√2 -----( 1 )
***********************
We know the algebraic identity ,
a³ - b³ - 3ab( a - b ) = ( a - b )³
Or
a³ - b³ = ( a - b )³ + 3ab( a - b )
************************
x³ - 1/x³ = ( x - 1/x )³ + 3×x × 1/x(x - 1/x )
= ( x - 1/x )³ + 3( x - 1/x )
= ( 3 + 2√2 )³ + 3( 3 + 2√2 )
= ( 3 + 2√2 ) [ (3 + 2√2 )² + 3 ]
= ( 3 + 2√2 ) [ 9 + 8 + 12√2 + 3 ]
= ( 3 + 2√2 ) [ 20 + 12√2 ]
= 60 + 36√2+ 40√2 + 48
= 108 + 76√2
I hope this helps you.
: )
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