Question

pleas explain in detail​

Answer 1

Answer:

$\frac{33}{611}$

Step-by-step explanation:

Given that   $\sin\theta=\frac{15}{17}$  ⇒  $\sin^2\theta=(\frac{15}{17})^2=\frac{225}{289}$  

We also know that:

$\sin^2\theta+\cos^2\theta=1$

⇒ $\cos^2\theta=1-\sin^2\theta$

⇒ $\cos^2\theta=1-\frac{225}{289}$

⇒ $\cos^2\theta=\frac{64}{289}$

Substituting the values of $\sin^2\theta$ and $\cos^2\theta$ in the given question:

$\frac{3-4\cdot(\frac{225}{289} )}{4\cdot(\frac{64}{289} )-3}$

= $\frac{\frac{-33}{289} }{\frac{-611}{289} }$

We know that  $\frac{\frac{a}{b} }{\frac{m}{n} } =\frac{an}{bm}$

= $\frac{-33\cdot289}{-611\cdot289}$

= $\frac{33}{611}$             Answer

Answer 2

Answer:

Please see the attachment