Question

pleas solve it guys.........................​

Answer 1

Step-by-step explanation:

$\frac{1}{x} - \frac{1}{x + b} = \frac{1}{a} - \frac{1}{a + b} \\ \frac{x + b - x}{x(x + b)} = \frac{(a + b) - a}{a(a + b)}$

$ab(a + b) = bx(x + b) \\ a {}^{2} b + ab {}^{2} - bx {}^{2} - b {}^{2}x = 0 \\ a {}^{2} b - bx {}^{2} + ab {}^{2} - b {}^{2} x = 0 \\ b(a {}^{2} - x {}^{2} ) + b {}^{2} (a - x) = 0 \\ b(a - x)(a + x) + b {}^{2}(a - x) = 0 \\ b(a - x)(a + x + b ) = 0$

therefore,

(a-x)=0

x=a

and

(a+x+b)=0

x=-(a+b)