Question

pleas solve this question need urgently.

Answer 1

The initial velocity of the ball
u
Now, from the displacement relationship,
s = u*t + 1/2at^2
now, the acceleration is acceleration due to gravity which is against the velocity of the ball, thus it will be -g
Hence,
s = ut - 1/2gt^2, which is the quadratic equation, hence the trajectory will be parabolic...
at the highest point, v = 0
thus, u - gt = 0
or t = u/g
thus,
s = u^2/g - 1/2*g*(u/g)^2
or, s = u^2/(2g)

Thus, the correct graph would be (2)