Math, asked by siddhantrahate, 1 year ago

pleas tell the answer.
will give brainlist​

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Answered by mahimaacs2002
0

Answer: The complex number will be purely real if cosѲ = 0

cosѲ = cos90°

Ѳ=90

If you are asking for (1+i)^n then n = 4

((1+i)^2)^2

(1+i^2+2i)^2

(1-1+2i)^2

(2i)^2

4i^2

= -4

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