pleas tell the answer.
will give brainlist
Attachments:

Answers
Answered by
0
Answer: The complex number will be purely real if cosѲ = 0
cosѲ = cos90°
Ѳ=90
If you are asking for (1+i)^n then n = 4
((1+i)^2)^2
(1+i^2+2i)^2
(1-1+2i)^2
(2i)^2
4i^2
= -4
Similar questions
English,
7 months ago
Chemistry,
7 months ago
World Languages,
1 year ago
Computer Science,
1 year ago
Biology,
1 year ago
Math,
1 year ago