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Hey friend !
Here's your answer
========================>
1.) Expressing the equation 3x =5y +7 into ax + by + c =0
3x -5y -7 =0. is the answer for above question
The value of c is 7
2.) Given two equations ,
3x + y =2
5x -2y =7
and given ( -2 , 1 )
Here x can be taken as -2 and y as 1
Now substituting above values in equations .
3 (-2) + (1) = 2
-6 + 1 =2
-5 = 2
Second equation
5 (-2) - 2(1) =7
-10 -2 = 7
-12 =7
LHS is not equal to RHS in the above case.
So, the values of x and y are wrong.
# Hope it helps #
Here's your answer
========================>
1.) Expressing the equation 3x =5y +7 into ax + by + c =0
3x -5y -7 =0. is the answer for above question
The value of c is 7
2.) Given two equations ,
3x + y =2
5x -2y =7
and given ( -2 , 1 )
Here x can be taken as -2 and y as 1
Now substituting above values in equations .
3 (-2) + (1) = 2
-6 + 1 =2
-5 = 2
Second equation
5 (-2) - 2(1) =7
-10 -2 = 7
-12 =7
LHS is not equal to RHS in the above case.
So, the values of x and y are wrong.
# Hope it helps #
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